Simplify12b3+5c4+23+a2−6c5−2b3−4a2−11
WebbMath Resources/ algebra/ expression/ Simplify 3b2-2c5+23+a2-6c5-2b2-4a2-11 Question Gauthmathier6533 Grade 11· 2024-07-01 YES! We solved the question! Check the full … WebbAnswer (1 of 4): This is a classic. a^2(b - c) + b^2(c-a) + c^2(a - b) = a^2b - a^2c + b^2c - b^2a + c^2a-c^2b =a^2b - b^2a - a^2c + b^2c + c^2a -c^2b = ab(a - b) - c ...
Simplify12b3+5c4+23+a2−6c5−2b3−4a2−11
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Webba) Square the first term: (a3 )2 = a6 b) Square the second term: (2b3 )2 = 4b6 c) Place a minus sign between the two squares. Hence: (a3 − 2b3 ) (a3 + 2b3 ) = a6 − 4b6 Answer: 16x2 − 9y 2 Because factoring is “unmultiplying,” is should be a simple matter to reverse the process of Example 7. You Try It! EXAMPLE 8. Webb阅读并解决问题:对于形如x2+2ax+a2这样的二次三项式,可以用公式法将它分解成(x+a)2的形式,但对于二次三项式x2+2ax-3a2就不能直接运用公式了.此时,我们可以这样来处理:像这样,先添一适当项,使式中出现完全平方式,再减去这个项,使整个式子的值不变的方法称为“配方法”.(1)利用 ...
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